협동 메커니즘에서 FLP는 H-H 결합이 동시에 끊어지는 방식으로 H2와 상호작용한다.전자가 풍부한 아민은 H2 분자에 전자를 공급하고, 전자가 부족한 붕탄은 전자를 받아 H-H 결합이 끊어지고 H2가 방출된다.이 메커니즘은 한 단계에서 발생하며 명확하게 정의되지 않은 중간체입니다.
화학 원료를 구입해야하는 경우 요청 정보를 제출하여최신견적을받으십시오.
bis[2,4,6-tris(trifluoromethyl)phenyl]borane
4
2,2-Pyrrolidinedicarboxylic acid, 3-(2-ethoxy-2-oxoethyl)-4-(1-methylethenyl)-1-(trifluoroacetyl)-, diethyl ester, trans-
(1S,6R)-N-[N-(S)-(p-toluenesulfonyl)-p-toluenesulfonimidoyl]-3-methyl-6-(prop-1-en-2-yl)cyclohex-2-enamine
4-chloro-4-(4'-nitrophenyl)pentan-2-one
1-[2,4,6-trimethylphenylethynyl]-1,2-benziodoxol-3(1H)-one
1-Methylene-2-(acetoxymethyl)cyclohexane
benzaldehyde N,N-dimethyl-N-(p-bromobenzyl)hydrazonium bromide
2,5-diphenylhexa-1,5-diene-1,6-13C2
Diphenylmethyl-dichlormethyl-sulfon
[(2-tert-butyl-6-(4-fluorophenyl)pyridine(-2H))Pt(PPh3)]
10,10-dimethyl-7,9-diphenyl-8-azatricyclo<5.2.1.01,5>dec-8-ene
2,6-di-tert-butyl-4-methylphenyl (cyclohexen-3-yl)acetate
(2Z,3Z)-3-ethoxy-1,4-diphenyl-2-(phenylimino)but-3-en-1-one
(S)-3-Isopropylsulfanyl-cyclohexene
Spiro[2.4]hepta-4,6-diene-1-carboxaldehyde, 2,2-dimethyl-, (R)- (9CI)
N-methoxy-N-methyl-(S)-1-triphenylmethyl-aziridine-2-carboxamide